Acrate of potatoes of mass 19.5 kg is on a ramp with angle of incline 30.0° to the horizontal. the coefficients of friction are μs = 0.634 and μk = 0.339. find the frictional force (magnitude and direction) on the crate if the crate is sliding down the ramp.

95.64 N

Explanation:

Given

mass of potato is 19.5 kg

inclination of ramp

coefficient of static friction

Normal reaction on block will be N=mgcos30=165.66 N

Since crate is sliding and not moving therefore static friction acts

Sin component of weight =mgsin30=95.64

Static friction

since static friction is more therefore it adjust itself

so net frictional force will be 95.64 N

a) cold, dry

explanation:

continental polar masses are cold and dry air masses because the cold air cannot hold much moisture. as they move into warmer air, they can trigger precipitation.

there is no correct list among the choices you've provided.

the list might look something like this:

-- baby human

-- piccolo

-- flute

-- soprano singer

-- trumpet

-- tenor singer

-- trombone

-- baritone singer

-- baritone horn

-- bass singer

-- tuba

since i had to make up the list myself, i made it easy on myself, and i didn't try to shuffle the string instruments and woodwinds into it too.