Aboy pulls a 30.0-kg box with a 210-n force at 39° above a horizontal surface. if the coefficient of kinetic friction between the box and the horizontal surface is is 0.23 and the box is pulled a distance of 38.0 m, what is the work done by the friction force on the box?

W= - 1414.48 J  : Work done by the friction force on the box.

Explanation:

Work concept

The work (W) of a given force is defined as the product of the force (F) by the distance(d) in which the force acted.

W= F*d :in (Joules)  Formula (1)

Friction force concept

Ff=μk*N  Formula (2)

μk=coefficient of kinetic friction

N= Normal force

We apply Newton's first law for forces in the direction of the axis y

∑Fy=0 Equation (1)

The forces acting on the box in the direction of the axis and are the following:

We apply equation (1) and do the algebraic sum of forces in y

Fy+N-W=0

132.16+N-294=0

N= 294-132.16=161.84 N

We apply formula (2) to calculate Ff:

Ff= -0.23*161.84=-37,22N  The frictional force is negative because it goes in the opposite direction to the displacement.

We apply formula (1) to calculate the work done by the friction force on the box

W= - 37,22 N * 38 m = -1414.48 N*m = -1414.48 J

jupiter

explanation:

it is so massive and has such a strong gravitational pull its likely prevented the formation of a planet between itself and mars in the asteroid belt

subscribe to my yt channel yoongi jmz

follow my insta yoongi_jams

stan bts

ice to water 1 water to vapour 2 latent heat