The distance travelled by a particle in time t is given by s is equal to 2.5 metre per second t2 find the instantaneous speed at t= 5sec with full explanation

25 m/s

Explanation:

s = (2.5 m/s²) t²

Velocity is the first derivative of position with respect to time.

v = ds/dt

v = (5 m/s²) t

At t = 5 s:

v = (5 m/s²) (5 s)

v = 25 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s