Alunch pail is accidentally kicked off a steel beam on a building under construction. suppose the initial horizontal speed is 1.50 m/s. how far does the lunch pail fall after it travels 3.50 m horizontally? 8. if the building in problem 7 is 2.50 × 10 2 m tall, and the lunch pail is knocked off the top floor, what will be the horizontal displacement of the lunch pail when it reaches the ground?

1) 26.6 m

Along the horizontal direction, the lunch pail is moving with a uniform motion (constant speed), since there are no forces acting in this direction.

Therefore, the distance travelled horizontally after a time t is given by:

where we know

is the horizontal velocity

d = 3.50 m is the distance covered horizontally

Solving for t, we find the total time of the motion:

Now we know that the pail takes 2.33 s to fall to the ground. We can now consider the vertical motion of the pail, which is a free fall motion, so the vertical displacement is given by the equation

where, taking downward as positive direction:

u = 0 is the initial vertical velocity

is the acceleration of gravity

Substutting t = 2.33 s, we find how fat the pail has fallen:

2) 10.7 m

In this case, we know instead the vertical displacement:

Therefore, we can use the same equation again

To find the total time of motion:

We know that along the horizontal direction, the velocity is constant:

So, the horizontal distance covered in this time is

the bal will not change its velocity.

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this