Adragster completed a 402.3-(0.2500-mi) run in 5.023s. if the car had a constant acceleration, what was its acceleration and final velocity?

v = 80.092 m/s

a = 15.945 m/s²

Explanation:

Given,

The distance completed by the dragster, d = 402.3 m

The time taken by the dragster to complete that distance is, t = 5.023 s

The initial velocity of the dragster, u = 0

The final velocity of the dragster, v = ?

The acceleration of the dragster, a = ?

The velocity of the body is given by the formula

                                  v = d/t  m/s

Substituting the above values inn the equation

                                  v = 402.3 m / 5.023 s

                                     = 80.092 m/s

So, the velocity of the dragster is, v = 80.092 m/s

The acceleration of the body is given by the formula

                                   a = (v - u)/t  m/s²

Substituting the above values in the equation

                                      = (80.092 - 0) / 5.023

                                      = 15.945 m/s²

Hence, the acceleration of the dragster is, a = 15.945 m/s²

statement #3 on andre"s list is false.

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2