Apitcher throws a softball toward home plate. when the ball hits the catcher’s mitt, its horizontal velocity is 32 meters/second. the softball’s velocity goes to 0 meters/second in 0.8 seconds when caught. if the softball has a mass of 0.2 kilograms, what’s the force of the impact? use f = ma, where .
the force of the impact is
newtons

Force applied to stop the softball: - 8 N

See if they are asking for the absolute value of this, which will be 8 N.

Explanation:

In order to apply the formula F = m * a, we need to find the acceleration that is imparted on the ball to change its velocity from 32 m/s to zero m/s.

We use the formula for acceleration:

where the initial velocity is 32 m/s, the final velocity is 0 m/s, and the time (t) it took to make this change is: 0.8 seconds:

where the answer comes on given the units for the velocities and time used.

Then, knowing the mass of the softball, we can calculate the force applied:

So the absolute value of this force (force of impact) is 8 Newtons.

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.