The two blocks m = 20 kg and m = 96 kg are not attached to each other. the coefficient of static friction between the blocks is 0.40, but the surface beneath the larger block is frictionless. what is the minimum magnitude of the horizontal force f required to keep the smaller block from slipping down the larger block?

F = 8 N

Explanation:

Given,

The mass of the smaller block, m = 20 Kg

The mass of the larger block, M = 96 Kg

The coefficient of the static friction, μ = 0.4

The static friction force acting on a body is the minimum horizontal force that is required to keep the smaller block from slipping down the larger block. It is given by the formula,

                        F = μ · η   N

Where,      η  - normal force acting on the body

                       F = 0.5 x 20

                         = 8 N

Hence, the minimum horizontal force that is required to keep the smaller block from slipping down the larger block is, F = 8 N.

conduction, convection, radiation