Abullet of mass 3.7 g strikes a ballistic pendulum of mass 4.6 kg. the center of mass of the pendulum rises a vertical distance of 19 cm. assuming that the bullet remains embedded in the pendulum, calculate the bullet's initial speed.

v = 2401.09 m/s

Explanation:

It is given that,

Mass of the bullet,

Mass of a ballistic pendulum,

Vertical distance, h = 19 cm = 0.19 m

Here, the conservation of energy follows as the kinetic energy of bullet is converted to the potential energy as :

..........(1)

V is the speed of the bullet and the pendulum at the moment of collision.

Using the conservation of linear momentum as :

v is the speed of the bullet before collision.

v = 2401.09 m/s

So, the bullet's initial speed is 2401.09 m/s. Hence, this is the required solution.

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).

i think they are all correct

explanation:

they seem good