Acube of iron and a cube of wood, each having a volume of v = 1.65 10-4 m3, are each placed in a large beaker of water. the density of the wood is ϝwood = 3.73 102 kg/m3 and the density of the iron is ϝiron = 7.86 103 kg/m3. calculate the buoyant force on each.

Buoyant force on the wood = 0.603 N

Buoyant force on the iron = 12.722 N                  

Explanation:

We have given the cube of iron and cube of wood both have volume

Density of wood

And density of the iron

Acceleration due to gravity

We know that buoyant force is given by

So buoyant force on the wood =

So buoyant force on iron =

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