A3.0-cm-diameter tube is held upright and filled to the top with mercury. the mercury pressure at the bottom of the tube − the pressure in excess of atmospheric pressure-is 48 kpa. how tall is the tube?

Given a tube of diameter d, = 3cm = 0.03m

Pressure Balance

Mercury pressure at the tube bottom Pₓ = Pa + ρgh

where

Pa = Atmospheric pressure = 101kpa

ρ = Density of mercury = 13,546kg/m3

g = acceleration due to gravity

h = height of the tube?

Given

Bottom pressure in excess of the atmospheric pressure = 48kPa = Pₓ - Pa

Therefore, 48kPa = ρgh

h = 48(kN/m2)/ρg

h = 48,000kgms⁻²m⁻²/(13546kgm⁻³ x 9.81ms⁻²)

h = 0.36m

the tube is 36cm tall

a electromagnetic waves

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.