Physics, 29.11.2019 06:31 ineedhelpasap12
(a) how long will it take an 850-kg car with a useful power output of 40.0 hp (1 hp equals 746 w) to reach a speed of 15.0 m/s, neglecting friction? (b) how long will this acceleration take if the car also climbs a 3.00-m high hill in the process?
Answers: 2
, b) 
![\Delta t = \frac{(850\,kg)\cdot \left[\left(9.807\,\frac{m}{s^{2}} \right)\cdot (3\,m) + \frac{1}{2}\cdot \left(15\,\frac{m}{s} \right)^{2}\right]}{(40\,hp)\cdot \left(\frac{746\,W}{1\,hp} \right)}](/tpl/images/0395/8152/325d4.png)
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