Physics, 07.12.2019 06:31 gudon986732

Acar of mass m, traveling at constant speed, rides over the top of a round hill. how do the normal force of the road on the car and the gravitational force of the earth on the car compare at this point? a. n > mg b. n < mg c. n = mg

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The normal force will be lower than the gravitational force acting on the car. Therefore the answer is N < mg, which is option B.

Explanation:

Over a round hill, the centripetal force acting toward the the radius of the hill supports the gravitational force (mg) of the car. This notion can be expressed mathematically as follows:

At the top of a round hill

Normal force = Gravitational force - centripetal force

At the foot of a round hill

Normal Force = centripetal force + Gravitational force

Answer from: Quest

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more

Answer from: Quest

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Acar of mass m, traveling at constant speed, rides over the top of a round hill. how do the normal f...

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