Question 4 1 pts
The actual efficiency of an engine can be calculated using the ratio of
the energy of the reservoir compared to the engine intake energy.
Calculate the ideal efficiency and the actual efficiency of a heat engine if
the engine takes in 100 kJ of energy from a source at 810 K and expels
45 kJ to a reservoir at 350 K. Round to the nearest hundredth.
Ideal = 0.26
Actual - 0.45
Actual - 0.65
Ideal - 0.57

v=ir = 3x15 =45 v

the maxium height is 34m/s

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m