Suppose you have 600.0 grams of room temperature water (20.0 degrees celsius) in a thermos. you drop 90.0 grams of ice at 0.00 degrees celsius into the thermos and shut the lid. (a) what is the equilibrium temperature of the system? (b) how much ice is left (in grams)?

= 7.02 ° C

Explanation:

The liquid water gives heat to melt the ice (Q₁) maintaining the temperature of 0 ° C and then the two waters are equilibrated to a final temperature.

Let's start by calculating the heat needed to melt the ice

Q₁ = m L

Q₁ = 0.090 3.33 10⁵

Q₁ = 2997 10⁴ J

This is the heat needed to melt all the ice

Now let's calculate at what temperature the water reaches when it releases this heat

Q = M (T₀ -)

Q₁ = Q

    = T₀ - Q₁ / M

= 20.0 - 2997 104 / (0.600 4186)

= 20.0 - 11.93

= 8.07 ° C

This is the temperature of the water when all the ice is melted

Now the two bodies of water exchange heat until they reach an equilibrium temperature

Temperatures are

Water of greater mass     T₀₂ = 8.07ºC

Melted ice                         T₀₁ = 0ºC

M (T₀₂ - ) = m ( - T₀₁)

      M T₀₂ + m T₀₁ = m + M

= (M T₀₂ + 0) / (m + M)

= M / (m + M) T₀₂

let's calculate

= 0.600 / (0.600 + 0.090) 8.07

      = 7.02 ° C

the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.