Atruck accelerates uniformly from rest to 17.5 m/s in 6.1 s along a level stretch of road. determine the average power (in w) required to accelerate the truck for the following values of the weight (ignore friction).

P=m*50.225W

just replace values of weight to find out Power.

You did not give value of weight in Question

Explanation:

a=vf-v1/t

a=17.5/6.1

a=2.87m/s²

F=ma

F=m*2.87 m/s²

P=F*v

P=m*2.87m/s²*17.5m/s

P=m*50.225 W

from

explanation:

wind is defined by the direction it blows from.   for example, a wind blowing from north to south is called a northerly wind.

d.7.5cm is your answer