Abarge is 10.0 m wide and 60.0 m long and has vertical sides. the bottom of the hull is 12.0 m below the water surface. what are the weight of the barge and its cargo, if it is floating in freshwater?

7.06MN

Explanation:

length = 60m

Width = 10m

Height = 12 m

Let Fb = Force buoyant

Fb = pgV = mg

p(density) = rho

The density of water in this case = 1000

g = 9.8 m/s

Volume = lenght*width*height

= 60*10*12

= 7200m^3

So we have

(1000 * 9.8 * 7200) = mg

= 70560000

7.06 MN

multiply 2kg by latent heat of vap