Abicyclist passing through a city accelerates after he passes the sign post marking the city limits at x=0. his acceleration is constant at 5.0 m/s^2 east. at time t1= 0.0s, he is located at x1 = 6.0m and has a velocity v1=4.0 m/s east.

a) find his position and velocity at t2= 2.0s.

b) how far is he from the sign post when his velocity is 6.0 m/s.

A. 24 m, 14 m/s

B. 8.0 m

Explanation:

Given:

x₀ = 6.0 m

v₀ = 4.0 m/s

a = 5.0 m/s²

t = 2.0 s

A. Find: x and v

x = x₀ + v₀ t + ½ at²

x = (6.0 m) + (4.0 m/s) (2.0 s) + ½ (5.0 m/s²) (2.0 m/s)²

x = 24 m

v = at + v₀

v = (5.0 m/s²) (2.0 s) + (4.0 m/s)

v = 14 m/s

B. Find x when v = 6.0 m/s.

v² = v₀² + 2a (x − x₀)

(6.0 m/s)² = (4.0 m/s)² + 2 (5.0 m/s²) (x − 6.0 m)

x = 8.0 m

they are non-matter

explanation:

they are non-matter. basically, any type of energy or any abstract concept is an example of something that does not matter. other examples include dreams, magnetism, radio, and hate

wavelength divides in half and speed stays the same.