The height of a helicopter above the ground is given by h = 3.15t3, where h is in meters and t is in seconds. at t = 2.10 s, the helicopter releases a small mailbag.
how long after its release does the mailbag reach the ground?

The mailbag will take 2.44 seconds to reach the ground.

Explanation:

The height of a helicopter above the ground is given by:

Height of helicopter at t = 2.10 seconds

The helicopter releases a small mailbag from the height of 29.17 m.

The initial velocity of mailbag = u = 0 m/s

Duration in which mailbag will reach the ground = T

Acceleration due to gravity = g =

Using second equation of motion ;

We have , s = 29.17

u = 0 m/s

t = T

Solving for T, we gte :

T = 2.44 seconds

The mailbag will take 2.44 seconds to reach the ground.

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