Aload consists of a 70-ω resistor in parallel with a 90-μf capacitor. if the load is connected to a voltage source vs(t) = 160cos 2000t, find the average power delivered to the load.

Power delivered by the source will be 182.912 watt

Explanation:

We have given a load is consist of a resistor of 70 ohm in parallel with capacitance

Voltage source is given

So maximum value of voltage source is 160 volt

So rms value

We know that average power delivered by the source will be equal to average power absorbed by the resistor

So power absorbed by the resistor

So power delivered by the source will be 182.912 watt

an obstruction

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explanation:

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