What is the change in temperature of a 2.50 l system when its volume is reduced to 1.00 l if the initial temperature was 298 k?

-178.8 K

Explanation:

From Charles law,

V₁/T₁ = V₂/T₂ Equation 1

Where V₁ = Initial volume, T₁ = Initial Temperature, V₂ = Final volume, T₂ = Final Temperature.

Making T₂ the subject of the equation

T₂ = V₂T₁/V₁ Equation 2

Given: V₂ = 1.00 L, V₁ = 2.5 L, T₁ = 298 K.

Substitute into equation 2

T₂ = 1.00(298)/2.5

T₂ = 119.2 K.

But,

Change in temperature = T₂ - T₁ = 119.2-298

Change in temperature = -178.8 K.

Hence the change in temperature = -178.8 K

the answer is d. 4

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answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.