83. A racquet ball is struck in such a way that it leaves the

racquet with a speed of 4.87 m/s in the horizontal

direction. When the ball hits the court, it is a horizontal

distance of 1.95 m from the racquet. Find the height of

the racquet ball when it left the racquet.

0.7864m

Explanation:

Ignore air resistance (the ball's horizontal speed stays constant), the time it takes for the ball to travel 1.95 m horizontally at the rate of 4.87 m/s.

t = 1.95 / 4.88 = 0.4s

This is also the time it takes to fall vertically with gravitational acceleration of g = 9.81 m/s2. We can use the following equation of motion to estimate the vertical distance:

it is a negative acceleration

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j