Finally, you are ready to answer the main question. Cheetahs, the fastest of the great cats, can reach 50.0 miles/hour miles/hour in 2.22 s s starting from rest. Assuming that they have constant acceleration throughout that time, find their acceleration in meters per second squared.

10.1m/s²

Using one of the equations of motion as follows;

v = u + at       ----------------------(i)

where;

v = final velocity of the body (Cheetahs) = 50.0 miles/hour

u = initial velocity of the body = 0 (since they start running from rest)

a = acceleration/deceleration

t = time taken for the motion = 2.22s

First convert the final velocity (v) from miles/hour to m/s

Remember that;

1 mile = 1609.34m

1 hour = 60 x 60s = 3600s

Therefore;

50miles/hour = = = 22.35m/s

=> v = 22.35m/s

Substituting the values of v, u and t into equation (i) gives;

=> 22.35 = 0 + a (2.22)

=> 22.35 = 2.22a

=> a = = 10.07m/

=> a = 10.1m/s² (to 1 decimal place)

Therefore the acceleration in m/s² is 10.1

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get