If, as soon as the angular speed is ω = 32 rad/s, the force is immediately removed and a mass m = 1.3 kg is dropped at r = 0.25 m on the disc and sticks there, what would be the new rotational velocity of the disc in rad/s?

Answer

given,

angular speed of disk = 32 rad/s

mass dropped, m = 1.3 Kg

radius, r = 0.25 m

new rotational velocity = ?

now,

Initial rotational inertia of the disk

Assuming the mass and the radius of the disk is equal to 7.5 Kg and 0.85 m respectively

now,

Rotational inertia after mass is dropped on it

using angular momentum conservation

 I₁ω₁ =  I₂ω₂

 2.71 x 32 = 2.79 x ω₂

 ω₂ = 31 rad/s

new angular velocity of the disk is   ω₂ = 31 rad/s

diagram is missing, but i will try to explain your doubt.

answer:

amplitude is the maximum displacement or distance moved on a point of a vibrating body or wave measured from its equilibrium position.it is equal to half the length of vibration path.

thermal energy is the answer