By how much does a 65.0-kg mountain climber stretch her 0.800-cm diameter nylon rope when she hangs 35.0 m below a rock outcropping? Young's modulus for the nylon rope is 5×109N/m2.

Explanation:

Expression for Young's modulus is represented as follows.

            Y =

               =

where,   Y = Young's modulus

              F = force which acts perpendicular to the surface

              A = area of the surface

          = original length of the rope

          = elongation in the rope

The given data is as follows.

          r = 0.008 m,   mass (m) = 65 kg,    g = 9.8 m/s

         S =

          = 35 m

Force perpendicular to the surface is calculated as follows.

                   F = mg

                     =

                     = 637 N

and,     Area =

                     =

                     =

Putting the given values into the above formula as follows.

                    =

                     =

                     =

Thus, we can conclude that by does a 65.0 kg mountain climber stretch her 0.800 cm diameter nylon rope.

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr