A knife thrower throws a knife toward a 300 g target that is sliding in her direction at a speed of 2.45 m/s on a horizontal frictionless surface. She throws a 22.5 g knife at the target with a speed of 36.0 m/s. The target is stopped by the impact and the knife passes through the target. Determine the speed of the knife (in m/s) after passing through the target.

Explanation:

We shall apply conservation of momentum  here because it is a case of inelastic collision

u₁ , u₂ initial velocity of knife and target . v₁ , v₂ be their final velocity.

m₁ u₁ + m₂u₂ = m₁v₁ + m₂v₂

u₂ will be negative as it is coming from opposite direction.

36 x 22.5 - 300 x 2.45 = 22.5 x v₁ + 0

810 - 735 = 22.5 x v₁

v₁ = 3.33 m /s

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation:

spectral lines lyman is one set