A ball of mass 0.220 kg that is moving with a speed of 6.3 m/s collides head-on and elastically with another ball initially at rest. Immediately after the collision, the incoming ball bounces backward with a speed of 3.6 m/s. (Assume the positive direction is forward.)

(a) Calculate the velocity of the target ball after the collision.
(b) Calculate the mass of the target ball.

(a) Velocity of target is 2.7 m/s.

(b) Mass of target is 0.807 kg.

Explanation:

Mass of ball

initial speed of the ball

Final speed of the ball

Part (a) The second ball is initially at rest. So, by the conservation of momentum,

Now, the velocity of approach is equal to the velocity of separation,

Part (b): From equation (1),

i believe it is b. what was the cause of the big bang

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6 cos 34, 6 sin 34 trig