A 5.00-m-long, 430 kg steel beam extends horizontally from the point where it has been bolted to the framework of a new building under construction. A 71.0 kg construction worker stands at the far end of the beam. What is the magnitude of the torque about the point where the beam is bolted into place?

Magnitude of torque=14014N.m

Explanation:

Torque is given by Force× perpendicular distance

Net Force= Torque(total) + Torque(worker)

Torque(net)= F(steel)×L/2 + F(worker)×L

Torque (net)= mg × L/2 + mg× L

Torque(net)= (430×8.8×(5/2)) + ( 71×9.8 ×5)

Torque(net)= 10535 + 3479

Torque(net)= 14014N.m

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