A long solenoid (1000 turns/m) carries a current of 25 mA and has an inside radius of 2.0 cm. A long wire which is parallel to and 4.0 cm from the axis of the solenoid carries a current of 6.0 A. What is the magnitude of the magnetic field at a point on the axis of the solenoid

B = 0.031T

Explanation:

Given n1 = 1000turn/m

i1 = 25A

μo = 4π ×10‐⁷ Wb/A•m

B1 = μo×i1×n1

B1 = 4π ×10‐⁷ × 25 × 1000 = 0.031T.

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