Effects of Environmental Conditions on Transpiration Environmental Condition Water Loss(mL/m^2/hr) Standard room 4 Bright light 6 Wind 8 Misting around plant 2 Polluted environment 3 Which of the conditions serves as the control? (A) Standard Room (B) Bright Room (C) Wind (D) Misting around plant (E) Pollute

A. Standard Room

Explanation:

-Transpiration is the process of water movement through a plant and its evaporation from aerial parts, such as leaves, stems and flowers.

-A standard room luck wind and other essentials necessary for an effective transpitration process.

-Hence, it will act a control to the experiment.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

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explanation: