A 0.780 m long section of cable carrying current to a car starter motor makes an angle of 60.0° with the Earth's 5.50 ✕ 10−5 T field. What is the current (in A) when the wire experiences a force of 7.00 ✕ 10−3 N?

The current is 188.17Amperes

Explanation:

The formula for calculating the force carrying current on a conductor placed in a magnetic field is expressed as shown;

F = BILsin(theta) where;

F is the force on the conductor = 7.00 ✕ 10^−3 N

B is the earth's magnetic field = 5.50 ✕ 10^−5 Tesla

I is the current = ?

L is the length of the conductor = 0.78m

theta is the angle that the conductor make with the earth's magnetic field = 60.0°

Making the current I the subject of the formula from the equation gives;

I = F/BLsin(theta)

Substituting the given data's in the formula to get current in the wire;

I = 7.00 ✕ 10^−3/(5.50 ✕ 10^−5 × 0.78 × sin60°)

I = 7.00×10^−3/3.72×10^-5

I = 188.17Amperes

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.

they should be similar or the same