An object of mass m is attached to a vertically oriented spring. The object is pulled a short distance below its equilibrium position and released from rest. Set the origin of the coordinate system at the equilibrium position of the object and choose upward as the positive direction. Assume air resistance is so small that it can be ignored.

The motion is described by a set of explanations below

Explanation:

For the part A, the position of the moment is represented by the plot on each side in the far left. Because the mass has been pulled down, this can only assume the negative downward direction. Thus, graphs D and H will be negative on the far left at a position when the time t = 0.

For the part B, the position of the mass will be at point E.

For the part C, the mass will be at the position F. This is because the acceleration is a derivative of the velocity of the object as given by the following derivative equation:

where a = acceleration and v is the velocity.

uranium fissions/breaks up giving out energy and neutrons

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y