The electric field of a charge Q at a distance d away is measured as E What will the electric field measure at a distance 1/2 d away from the charge?

Correct  E₁ = 4 · E  The electric field increased four times

Explanation:

Given:

E - Electric field  at distance d

E₁ - Electric field  at distance d₁

Q - Charge of an object

d₁ = (1/2) d

The formula by which the electric field is calculated is:

E = k Q / d²  

Electric field at a distance d₁

E₁ = k Q / d₁²

We will form their quotient

E₁ / E = ((k Q) / d₁²) / ((k Q) / d²)

When the constant k and the charge Q is canceled we get:

E₁ / E = (1 / d₁²) / (1 / d²) = d² / d₁² = d² /  ((1/2) d)² = 1 /(1/4) = 4

E₁ = 4 · E

The electric field increased four times

God is with you!!!

d. platinum would have the greatest temperature increase because it has the lowest specific heat.

it's when something is going so fast it makes a loud noise, breaking the sound barrier, for example: a jet makes a loud noise, not only cause of the jet but because they reached a point where they went so fast that you can year the noise from various parts, kinda like a police car, lets say the car was going   so fast that you hear the siren of the cop car right next to you, but the car is probably a mile a way, it's cos the siren was next to you a few seconds if you understand me