3.27 moles of an ideal gas has a pressure of 125000 Pa at 15.0 ° C What is the volume of the gas?

62.86 dm3

Explanation:

Given that:

Volume of water V = ?

Temperature T = 15°C

Convert Celsius to Kelvin

(15°C + 273 = 288K)

Pressure P = 125000 Pa

Convert pressure in Pascal to atmosphere,

If 101,325 Pascal = 1 atm

125000 Pascal = Z

To get Z, cross multiply

Z x 101325 Pa = 125000 Pa x 1 atm

Z = 125000 Pa / 101325 Pa

Z = 1.23 atm

Number of moles of gas = 3.27

Molar gas constant R is a constant with a value of 0.0821 atm dm3 K-1 mol-1

Then, apply ideal gas equation

pV = nRT

1.23atm x V = 3.27 moles x (0.0821 atm dm3 K-1 mol-1 x 288K)

1.23atm x V = 77.32 atm dm3

V = (77.32 atm dm3 / 1.23 atm)

V = 62.86 dm3

Thus, the volume of the gas is 62.86 dm3

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increase masses, decrease separation