One type of BB gun uses a spring-driven plunger to blow the BB from its barrel. Calculate the spring constant of its plunger’s spring if you must compress it 0.283 m to drive the 0.0500-kg plunger to a top speed of 26.3 m/s. Assume that the barrel of the BB gun is horizontal.

431.83 N/m

Explanation:

Applying the law of conservation of energy,

From the question,

The kinetic energy of the plunger = energy stored in the spring

1/2mv² = 1/2ke² Equation 1

Where m = mass of the plunger, v = velocity of the plunger, k = spring constant of the spring, e = compression.

make k the subject of the equation

k = mv²/e² Equation 2

Given: m = 0.05 kg, v = 26.3 m/s, e = 0.283 m

Substitute into equation 2

k = 0.05(26.3²)/0.283²

k = 34.5845/0.080089

k = 431.83 N/m

answer: b.

explanation:

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is