A new metal alloy is found to have a specific heat capacity of 0.321 J/(g⋅∘C). First, 44.5 g of the new alloy is heated to 100. ∘C. Then, it is placed in an ideal constant-pressure calorimeter containing 175 g of water (Vs, water=4.184 J/(g⋅∘C)) at an initial temperature of 20.0 ∘C. What will the final temperature of the mixture be after it attains thermal equilibrium

The final temperature is 21.531°c

Explanation:

Heat gained by the water = heat lost by the metal

Heat gained = (m)(c)(∆tita)

Where m = mass

C = specific heat capacity

∆tita = temperature change

X = equilibrium temperature

So

Heat gained by water

= 175*4.185*(x-20)

= 732.2x - 14644

Heat lost by metal

= 44.5*0.321*(100-x)

=1428.45 -14.2845x

So

1428.45 - 14.2845x = 732.2x - 14644

1428.45+14644= 732.2x + 14.2845x

16072.45= 746.4845x

16072.45/746.4845= x

21.531 = x

The final temperature is 21.531°c

the force required to move the cart is divided by three or 33.33 n.

12000j is work done