Two flywheels of negligible mass and different radii are bonded together and rotate about a common axis (see below). The smaller flywheel of radius 21 cm has a cord that has a pulling force of 50 N on it. What pulling force (in N) needs to be applied to the cord connecting the larger flywheel of radius 34 cm such that the combination does not rotate

The pulling force applied to the cord connecting the larger flywheel is 30.88 N

Explanation:

Given;

the radius of the smaller flywheel, r₁ = 21 cm

force on the cord of the smaller flywheel, F₁ = 50 N

the radius of the larger flywheel, r₂ = 34 cm

The torque on each flywheel is equal, since there is no rotation.

τ = Fr

where;

τ is torque on each flywheel

F is the force on the cord of each flywheel

r is the radius of each flywheel

F₁r₁ = F₂r₂

Therefore, the pulling force applied to the cord connecting the larger flywheel is 30.88 N

1/0.14nm = 10^10/1.4 a lot

a.metals can become magnetic if they have many spinning electrons that create magnetic fields.d.only some metals are attracted by magnets; these metals are called ferromagnetic.

d.wrapping an insulated wire around a metal with ferromagnetic properties and applying an electric current.