In a double‑slit interference experiment, the wavelength is λ = 507 nm , the slit separation is d = 0.180 mm , and the screen is D = 33.0 cm away from the slits. What is the linear distance Δ x between the ninth order maximum and the second order maximum on the screen?

i think the answer would be reserve.

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initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft