An electron is released from rest at a distance of 9.00 cm from a proton. If the proton is held in place, how fast will the electron be moving when it is 3.00 cm from the proton

v = 61.09m/s

Explanation:

In order to calculate the speed of the electron when it is 3.00cm from the proton, you first calculate the acceleration of the electron, produced by the electric force between the electron and the proton. By using the second Newton law you have:

    (1)

m: mass of the electron = 9.1*10^-31kg

q: charge of electron and proton = 1.6*10^-19C

r: distance between electron and proton = 9.00cm = 0.09m

k: Coulomb's constant = 8.98*10^9Nm2/C^2

You solve the equation (1) for a, and replace the values of the other parameters:

Next, you use the following formula to calculate the final speed of the electron:

      (2)

vo: initial speed of the electron = 0m/s

a: acceleration = 3.11*10^4m/s^2

x: distance traveled by the electron

When the electron is at 3.00cm from the proton the electron has traveled a distance of 9.00cm - 3.00cm = 6.00cm = 0.06m = x

You replace the values of the parameters in the equation (2):

The speed of the electron is 61.09m/s

answer: i think he can see forward ten seconds and move forward ten seconds but giorno can undo his actions with ger.

explanation:

the earths atmosphere is made up of nitrogen and oxygen. solids can turn into gasses through a process called sublimation. sublimation is the transition of a substance directly from the solid to the gas phase, without passing through the intermediate liquid phase.

hope this : d