The capacitor is originally charged. How does the current I in the ammeter behave as a function of time after the switch is closed? 1. I = 0 always.

2. I = constant, not equal to 0.

3. I increases, then is constant.

4. I instantly jumps up, then slowly decreases.

5. None of the above.

The current in the ammeter is zero.

(1) is correct option.

Explanation:

Given that,

The capacitor is charged.

We need find the current after closed switched

We know that,

When switch is closed then the capacitor behave as a short circuit, and the all current flows through it. the current is zero.

Then, the ammeter reads zero.

Hence, The current in the ammeter is zero.

(1) is correct option.

the answer would be c. motion and direction

i hope this : )

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west