A hockey puck moves 26 meters northward, then 12 meters southward, and finally 6 meters northward what is the distance and the displacement? PLEASE HELP MEEE

The displacement is 20 m northward.

The distance is 44 m

Explanation:

Let northward motion be in positive direction

Let southward motion be in negative direction

Dispalcement is the shortest path covered by the hockey puck at a specified direction.

The dispalcement of the hockey puck will be calculated as;

Displacement = 26 m northward - 12m southward + 6 m northward

Displacement =  20 m in northward direction

Distance is the total path covered by the hockey puck.

Distance = 26 m + 12m + 6 m

Distance = 44 m

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

i don't understand is there any other way you can rephrase it plz let me know in the comments and i will do it.

explanation: