The meter was originally defined so that the period of a meter-long simple pendulum would be exactly 2.00 second. (Was your measured value close to this?) Given the relationship, T^2 alpha L (T^2 is proportional to L) what would be the length of a simple pendulum, in centimeters, with a period of exactly one second?

Explanation:

Given that,

Initial length of simple pendulum,

Initial time period,

We need to find the length of the simple pendulum when the period is exactly 1 second.

We know that the time period of simple pendulum is given by :

Put all values and find L₂

So, the length of the pendulum with a period of exactly one second is 25 cm.

i think it's 35 meters

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j