An observer recorded the following data for the motion of a car undergoing constant acceleration. Time (s)
3.0
5.0
6.0
Speed (m/s)
4.0
7.0
8.5
What was the magnitude of the acceleration of the car?
4.5 m/s2
O 2.0 m/s2
3.0 m/s2
1.5 m/s2

Option D) 1.5 m/s² is the correct answer.

The magnitude of the acceleration of the car is 1.5 m/s².

given the data in the question;

record of the observation;

Time(s)      Speed(m/s)

3.0                4.0

5.0                7.0

6.0                8.5

Since its undergoing constant acceleration, we can make use any two from the three data recorded.

So, lets consider motion between t₁ = 3.0s and t₂ = 5.0s

Initial velocity at t₁ ; u = 4.0 m/s

final velocity at t₂; v = 7.0 m/s

Now, Time Elapsed;

To determine the magnitude of acceleration "a", we use the first equation of motion which says;

we make "a" the subject of the formula

so we substitute in our values;

Therefore, the magnitude of the acceleration of the car is 1.5 m/s².

Option D) 1.5 m/s² is the correct answer.

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1.5 m/s^2

hope that helps

probably not the "magnets"in the magnet, so to speak, are thought to be electrons orbiting in shells. vurrent loops two sides to the loop