A racehorse coming out of the gate accelerates from rest to a velocity of 12.0 m/s due west in 2.30 s. What is its average acceleration?
27.6 m/s^2
5.22 m/s^2
-5.22 m/s^2
-27.6 m/s^2
-0.19 m/s^2
O 0.19 m/s^2

5.22 m/s²

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Final velocity (v) = 12 m/s

Time (t) = 2.3 s

Acceleration (a) =.?

Acceleration is defined as the change of velocity with time. Mathematically, it is expressed as:

Acceleration (a) = final velocity (v) – initial velocity (u) / time (t)

a = (v – u) /t

With the above formula, we can obtain the acceleration of the racehorse as follow:

Initial velocity (u) = 0 m/s

Final velocity (v) = 12 m/s

Time (t) = 2.3 s

Acceleration (a) =.?

a = (v – u) /t

a = (12 – 0) / 2.3

a = 12 /2.3

a = 5.22 m/s²

Therefore, the average acceleration of the racehorse is 5.22 m/s²

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000