Two workers are sliding 270 kg k g crate across the floor. One worker pushes forward on the crate with a force of 430 N N while the other pulls in the same direction with a force of 230 N N using a rope connected to the crate. Both forces are horizontal, and the crate slides with a constant speed. What is the crate's coefficient of kinetic friction on the floor?

The value is

Explanation:

From the question we are told that

   The mass of the crate is  

   The force applied by the first worker is  

   The force applied by the second worker is

Generally the kinetic frictional force between the crate and the floor is equal to the force applied by both worker , this is mathematically  represented as

Here   is the frictional force and this is mathematically represented as

So

=>  

=>  

v=ir = 3x15 =45 v