1. A ball rolls down a hill with a constant acceleration of 2.5 m/s^2. The ball starts at rest and travels for 4.0 seconds before it hits a wall and stops.
How far did the ball travel before it stopped? *
a. 8.0 m
b. 12 m
c. 16 m
O d. 20 m

D 20m

Explanation:

Distance =

where u = initial velocity, t  = time taken, a = acceleration

Since, the ball starts at rest, initial velocity = 0 m/s

Time = 4.0 seconds  (given)

Acceleration = 2.5 m/s^2  (given)

So, distance = 0*4 + (0.5 * 2.5 *4^2) = 20m

total distance travelled = 60 miles

total time taken =1.5 hours

average speed = total distance / total time

60 / 1.5

= 40

therefore, average speed = 40 m/h

happy to

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see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west