The blade of a windshield wiper moves through an angle of 90.0° in 0.397 s. The tip of the blade moves on the arc of a circle that has a radius of 0.376 m. What is the magnitude of the centripetal acceleration of the tip of the blade?

Explanation:

Given that,

The blade of a windshield wiper moves through an angle of 90.0° in 0.397 s

The radius of the circlular path is 0.376 m

We need to find the magnitude of the centripetal acceleration of the tip of the blade. Let it is a. The formula of the centripetal acceleration is given by :

v is velocity,

It moves through an angle of 90 degrees, it means

So,

So, the magnitude of the centripetal acceleration of the tip of the blade is .