What is the ratio of the radii of curvature for a proton and an an electron traveling through this apparatus

hello your question is incomplete below is the missing part of the question

Consider an experimental setup where charged particles (electrons or protons) are first accelerated by an electric field and then injected into a region of constant magnetic field with a field strength of 0.55 T.

answer :   ≈ 42

Explanation:

Ratio of the Radii of curvature for a proton and an electron travelling through this apparatus

= = 0.025 m / 5.94 * 10^-4 m = 42.08

Rp = 0.025 m ( calculated )

Re = 5.94 * 10^-4 ( calculated )

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get