A proton moves at a speed of 850 m/s in a direction perpendicular to a magnetic field with a magnitude of 0.70 T. What is the magnitude of the magnetic force on the proton?

The magnitude of the magnetic force on the proton is 9.532 x 10⁻¹⁷ N

Explanation:

Given;

speed of proton, v = 850 m/s

magnitude of magnetic field, B = 0.7 T

Charge of proton, q = 1.602 x 10⁻¹⁹ C

The magnitude of the magnetic force on the proton;

F = qvB

F = ( 1.602 x 10⁻¹⁹)(850)(0.7)

F = 9.532 x 10⁻¹⁷ N.

Therefore, the magnitude of the magnetic force on the proton is 9.532 x 10⁻¹⁷ N

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance         (d) = 3 feet

time taken to lift                         (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

                  1 h.p   = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

                      h.p = (force × distance)/ time

                            = (10 × 3)/ 10

                            = 30/10

                            = 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts

tbh i dont know ether