What is the rate of acceleration of a 2,000 kilogram truck if a force of 4,200 N is used to make it start moving forward?

2.1

Explain:
F = ma
a = F/m = 4,200/ 2,000
a = 2.1

2.1m/s^2 is the answer to
Your question. I hope that helps.

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

One splits the atoms and molecules  the other combines them