Your older brother has been dealing in gold business brings to you a cube of a stone of uniform sides and claims its gold. Having studied density, explain stating
all the instruments involved how you can affirm that the stone is gold.

Explanation:

The density of gold is 19.3 g/cm³. Thus, you can determine the density of the unknown cube by doing the following. Get a measuring cylinder (marked in cm³) that contains a certain volume of water (preferably above average but not close to been filled up). Get a weighing balance (that can read in grams) also.

Measure the mass of the unknown stone (using the weighing balance) and record. Take the initial volume of the water in the measuring cylinder and record (in cm³) and then drop the unknown stone inside the measuring cylinder gently (avoid splashes). Record the final volume of the cylinder after the unknown stone was dropped.

Then calculate the density of the stone by using the formula; mass ÷ change in volume

The change in volume can be determined by; Final volume - initial volume

If the answer obtained from the calculation (of the density of the stone) is not around 19.3 g/cm³ (say 19.3 ± 0.2), then the stone is not gold but if it is around 19.3 g/cm³, then the stone is gold.

i guess it’s a and b